4(3x-3)^2/3=36

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Solution for 4(3x-3)^2/3=36 equation: 


x in (-oo:+oo)

(4*(3*x-3)^2)/3 = 36 // - 36

(4*(3*x-3)^2)/3-36 = 0

(4*(3*x-3)^2)/3+(-36*3)/3 = 0

4*(3*x-3)^2-36*3 = 0

36*x^2-72*x-72 = 0

36*x^2-72*x-72 = 0

36*(x^2-2*x-2) = 0

x^2-2*x-2 = 0

DELTA = (-2)^2-(-2*1*4)

DELTA = 12

DELTA > 0

x = (12^(1/2)+2)/(1*2) or x = (2-12^(1/2))/(1*2)

x = (2*3^(1/2)+2)/2 or x = (2-2*3^(1/2))/2

36*(x-((2-2*3^(1/2))/2))*(x-((2*3^(1/2)+2)/2)) = 0

(36*(x-((2-2*3^(1/2))/2))*(x-((2*3^(1/2)+2)/2)))/3 = 0

(36*(x-((2-2*3^(1/2))/2))*(x-((2*3^(1/2)+2)/2)))/3 = 0 // * 3

36*(x-((2-2*3^(1/2))/2))*(x-((2*3^(1/2)+2)/2)) = 0

( x-((2*3^(1/2)+2)/2) )

x-((2*3^(1/2)+2)/2) = 0 // + (2*3^(1/2)+2)/2

x = (2*3^(1/2)+2)/2

( x-((2-2*3^(1/2))/2) )

x-((2-2*3^(1/2))/2) = 0 // + (2-2*3^(1/2))/2

x = (2-2*3^(1/2))/2

x in { (2*3^(1/2)+2)/2, (2-2*3^(1/2))/2 }

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